0.04x^2+-0.8x+2=0

Solution for 0.04x^2+-0.8x+2=0 equation:

0.04x^2+-0.8x+2=0

We add all the numbers together, and all the variables

0.04x^2-0.8x=0

a = 0.04; b = -0.8; c = 0;
Δ = b2-4ac
Δ = -0.82-4·0.04·0
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.8)-\sqrt{0.64}}{2*0.04}=\frac{0.8-\sqrt{0.64}}{0.08}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.8)+\sqrt{0.64}}{2*0.04}=\frac{0.8+\sqrt{0.64}}{0.08}
$